aContents:Magnetic field and origin of magnetic fieldUnit of magnetic fieldBiot-Savart lawApplication of Biot-Savart law: Magnetic field due to long straight conducting wire4.1 Introduction:Magnetic field & Origin of Magnetic field:● Magnetic field is a force field similar to that of Gravitational field and Electric field. ● Magnetic field is a region of space around a magnet within which if another magnet is brought, it experiences a force.It is a vector field and denoted by .● Electric field is created by electric charges (positive charges, negative charges or electric dipole) but in case of magnetism no such magnetic charges are proved to exist till date. Magnetic field is created by current. ● In a permanent magnet, magnetism is produced by orbital and spinning motion of electrons in an atom. Motion of electrons in an atom constitutes a circulating current, which creates magnetic field within the magnetic material.● Fundamental/basics origin of magnetism is a magnetic dipole or current carrying loop/circulating current.Units of Magnetic field:SI units:Tesla (T) or a
N
A.m.
. Magnetic field →
B
is sometime called “Magnetic fluxdensity” and hence it has another unit,a
weber
m2=Wb
m2
CGS units: Gauss (G); 1 T = 104G4.2 Biot-Savart LawAfter Oersted’s experiment had concluded that a current carrying conductor produces magnetic field around it, French physicists Jean Baptiste Biot and Felix Savart deduced an empirical law to determine the magnitude and the direction of the magnetic field that a current element may produce at any point in space around it.Current element: Current element is a small length segment of a current carrying conductor. It is a vector quantity having magnitude ∣Id→
l
∣and direction along the tangent drawn at that segment in the direction of current (shown in the figure-4.1).dl→NIIMr2→dB→P𝜃Fig.-4.1: Biot-Savart Law and Current ElementAccording to Biot-Savart lawi. dB∝ Iii. dB∝ dI andiii. dB∝1
r2Combining all one gets,dB∝Idl
r2.In vector form the law is written as d→
B
=𝜇0
4𝜋(Id→
l
×→
r
)
r3, where 𝜇0
4𝜋 is the proportionalityconstant having value 𝜇0
4𝜋=10-7TmA-1(or Wbm-1A-1). Scalar form of the complete formulato be used while solving numerical problems is dB=𝜇0
4𝜋(Idl sin 𝜃)
r2
Fig.-4.2: Right-hand Thumb Rule
Direction of dB:The direction of the dB is in the direction of →
dl
×→
r
,which can be determined easily by using ‘Right-hand thumb Rule’ for cross product. ‘Right-hand thumb Rule’ for cross product has been demonstrated in the figure-4.2:Biot-Savart law can be used to determine magnetic field produced by a current conductor of any arbitrary shape considering that to be made of many small current element.dB=𝜇0
4𝜋(Idl sin 𝜃)
r2suggests that the magnetic field is zero at a point on the axis of the current element as 𝜃=0 over there. The magnetic field due to current element will be the maximum at any point in the plane passing through the current element and perpendicular to the axis of the current element as 𝜃=90°4.3 Application of Biot-Savart LawMagnetic field due to long straight current conductor: Magnetic field produced by a long straight wire can be determined by using Bio-Savart law.Let us consider a long straight wire PQ (shown in the figure-4.3) carrying a current ; we wish to calculate magnetic field at M point created by the wire. Here a is the perpendicular distance from the point M to be to the conducting wire PQ. 𝜃1 is measured from the perpendicular (MN) to the down and is measured in the upward direction from the perpendicular (MN). To calculate magnetic for the wire first we consider a small current element →
dl
and position vector of the point M is →
r
.According to Biot-Savart law the magnetic field at M,d
a⇒a tan𝜃⇒dl=a sec2 𝜃d𝜃..............................................................(4.2)Putting the value ofdl and r into equation (4.1) we get,dB=𝜇0
4𝜋×I(a sec2 𝜃d𝜃)cos𝜃
a2 sec2 𝜃d𝜃⇒dB=𝜇0I
4𝜋acos𝜃d𝜃..........................................(4.3)To get the magnetic field created by the full wire one needs to integrate the equation (4.3) between the limit -𝜃1 and -𝜃2 that isB=Q2∫-Q1dB=𝜇0I
4𝜋aQ2∫-Q1cos𝜃d𝜃=𝜇0I
4𝜋a[sin𝜃1+𝜃2].........................................(4.4)Equation (4.4) gives the magnetic field produced by a finite wire in terms of the angles (𝜃1 and 𝜃2) subtended at the points of observation by the ends of the wire.QIPMINO90°d→
l
l𝜃𝜃𝜃2𝜃2a→
r
Fig.-4.3: Application of Biot-Savart Law for a long finite straight wire.● If the wire, PQ is infinitely long and the point M is in the middle then ● 𝜃1=𝜃2=𝜋
2 and hence B=𝜇0I
2𝜋a● If the wire, PQ is infinitely long and the point M is near Q then● 𝜃1=𝜋
2 and 𝜃2=0 and hence B=𝜇0I
2𝜋a● Magnetic field at any end of an infinitely long conducting wire is half of the value of the magnetic field at the middle i.e.,● B=1
2a
𝜇0I
2𝜋a
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